A body of 2 kg falls from rest. What will be its kinetic energy during the fall at the end of 2 s? (Assume g = 10 m/s2)

Given,

Mass of the body, m = 2kg


Initial velocity (u) = 0 m/s


Time (t) = 2s


Acceleration due to gravity (g) = 10m/s2


We need to find, Final velocity (v) =?


We know,


v = u + at


v = 0 + 10 x 2


v = 20 m/s


K.E = 1/2 (mv2)


K.E = 1/2 x 2 x (20)2


K.E = 400J


Hence, the Kinetic energy of the body during the fall at the end 2s = 400 J


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