Given equation of circle is x² + y² + ax + (1 - a)y + 5 = 0.

We know that for a circle x² + y² + 2ax + 2by + c = 0

⇒ Centre = (- a, - b)

⇒ Radius =

We need to find the values of ‘a’ such that the radius of the given circle does not exceed 5.

We know that the radius of a circle cannot be less than 0.

Let ‘r’ be the radius of the given circle.

⇒ 0≤r≤5

⇒

⇒

⇒ 0≤2a² - 2a - 19≤100

By trial and error method we get the set of values of ‘a’ as [ - 7.2, 8.2].

∴The integral values of ‘a’ are - 7, - 6, - 5, - 4, - 3, - 2, - 1,0,1,2,3,4,5,6,7,8.