If a = secx – tanx and b = cosecx + cotx, then show that ab + a – b + 1 = 0.
Given a = secx – tanx and b = cosecx + cotx
a 
and b 
LHS = ab + a – b + 1
= 0 = RHS
Hence proved.
24
If a = secx – tanx and b = cosecx + cotx, then show that ab + a – b + 1 = 0.
Given a = secx – tanx and b = cosecx + cotx
a and b
LHS = ab + a – b + 1
= 0 = RHS
Hence proved.