Given,

a₁ = 1 = a₂, a_n = a_n–1 + a_n–2, n>2

We can find the first five terms of a sequence by putting values of n

from 1 to 5

When n = 1:

a₁ = 1

When n = 2:

a₁ = 1

When n = 3:

a₃ = a_3–1 + a_3–2

⇒ a₃ = a₂ + a₁

⇒ a₃ = 1 + 1

⇒ a₃ = 2

When n = 4:

a₄ = a_4–1 + a_4–2

⇒ a₄ = a₃ + a₂

⇒ a₄ = 2 + 1

⇒ a₄ = 3

When n = 5:

a₅ = a_5–1 + a_5–2

⇒ a₅ = a₄ + a₃

⇒ a₅ = 3 + 2

⇒ a₅ = 5

∴ First five terms of the sequence are 1, 1, 2, 3, 5.