Which term of the sequence 12 + 8i, 11 + 6i, 10 + 4i, … is (a) purely real (b) purely imaginary ?
Given A.P is 12 + 8i, 11 + 6i, 10 + 4i, …
Here, a1 = a = 12 + 8i, a2 = 11 + 6i
Common difference, d = a2 – a1
= 11 + 6i – (12 + 8i) = 11 – 12 + 6i – 8i = -1 – 2i
We know, an = a + (n – 1)d where a is first term or a1 and d is common difference and n is any natural number
∴ an = 12 + 8i + (n – 1) -1 – 2i
⇒ an = 12 + 8i – n – 2ni + 1 + 2i
⇒ an = 13 + 10i – n – 2ni
⇒ an = (13 – n) + (10 – 2n)i
To find purely real term of this A.P., imaginary part have to be zero
∴ 10 – 2n = 0
⇒ 2n = 10
⇒ n = 5
Hence, 5th term is purely real
To find purely imaginary term of this A.P., real part have to be zero
∴ 13 – n = 0
⇒ n = 13
Hence, 13th term is purely imaginary