Find the 12th term from the end of the following arithmetic progression:

3, 5, 7, 9, … 201

A.P is known for Arithmetic Progression whose common difference = an – an-1 where n > 0


a = a1 = 3, a2 = 5, l = 201


Common difference, d = a2 – a1 = 5 – 3 = 2


We know, nth term from end, bn = l – (n – 1)d where l is last term or a1 and d is common difference and n is any natural number


b12 = 201 – (12 – 1)2


b12 = 201 – 24 + 2


b12 = 203 – 24


b12 = 179


Hence, 12thterm from end for the given A.P is 179


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