Find the 12th term from the end of the following arithmetic progression:

1, 4, 7, 10, … 88

A.P is known for Arithmetic Progression whose common difference = an – an-1 where n > 0


a = a1 = 1, a2 = 4, l = 88


Common difference, d = a2 – a1 = 4 – 1 = 3


We know, nth term from end, bn = l – (n – 1)d where l is last term or a1 and d is common difference and n is any natural number


b12 = 88 – (12 – 1)3


b12 = 88 – 36 + 3


b12 = 91 – 36


b12 = 55


Hence, 12thterm from end for the given A.P is 55


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