The first and the last term of an A.P. are a and l respectively. Show that the sum of the nth term from the beginning and the nth term from the end is a + l.
To prove: sum of the nth term from the beginning and the nth term from the end is a + l
We know, an = a + (n – 1)d where a is first term or a1 and d is the common difference, and n is any natural number, and nth term from the end is an’ = l – (n – 1)d
Now,
an + an’ = a + (n – 1)d + l – (n – 1)d
⇒ an + an’ = a + nd – d + l – nd + d
⇒ an + an’ = a + l
Hence Proved