If θ1, θ2, θ3, …, θn are in AP, whose common difference is d, show that

Given: θ1, θ2, θ3,…, θn is A.P


θ2 – θ1 = θ3 – θ2 = θ4 – θ3 =…………= θn – θn-1 = d (Common Difference)


Now,



Multiplying and dividing by sin d:




{ sin(A - B) = sin A cos B - cos A sin B}






Similarly,




Take L.H.S.:



Putting the value of (i), (ii) and (iii):





= R.H.S.


Hence Proved


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