If θ1, θ2, θ3, …, θn are in AP, whose common difference is d, show that
Given: θ1, θ2, θ3,…, θn is A.P
∴ θ2 – θ1 = θ3 – θ2 = θ4 – θ3 =…………= θn – θn-1 = d (Common Difference)
Now,
Multiplying and dividing by sin d:
{∵ sin(A - B) = sin A cos B - cos A sin B}
Similarly,
Take L.H.S.:
Putting the value of (i), (ii) and (iii):
= R.H.S.
Hence Proved