If cosA = – 24/25 And cosB = 3/5, where π <A < 3π/2 And 3π/2 <B < 2π, find the following:

(i) sin(A +B) (ii) cos(A +B)

Given cosA = -24/25 And cosB = 3/5 where π <A < 3π/2 And 3π/2 <B < 2π


A is in third quadrant And B is in fourth quadrant.


Here, sine function is negative.


We know that






Then,


(i) Sin(A +B)


We know that sin(A +B) = sinA cosB + cosA sinB






(ii) Cos(A +B)


We know that cos(A +B) = cosA cosB - sinA sinB






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