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If SinA = 1/2, cosB = , where π/2<A < π And 0 <B < π/2, find the following:
(i) tan(A +B)(ii) tan(A -B)
Given sinA = 1/2 And cosB = √3/2 where π/2 <A < π And 0 <B < π/2,
A is in second quadrant And B is in first quadrant.
In the second quadrant, the sine function is positive And cosine And tan functions are negative.
In first quadrant, All functions are positive.
We know that
Then,
(i) tan(A +B)
We know that
= 0
(ii) tan(A –B)
We know that
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