RD Sharma - Mathematics

Book: RD Sharma - Mathematics

Chapter: 7. Values of Trigonometric Functions at Sum of Difference of Angles

Subject: - Class 11th

Q. No. 17 of Exercise 7.1

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17

Prove that:

π/12 = 15° And π/6 = 30°


We have 15° + 30° = 45°


tan(15° + 30°) = tan 45°


We know that



tan15° + tan30° = 1 – tan15° tan30°


tan15° + tan30° + tan15° tan30° = 1


Hence, proved.


Chapter Exercises

More Exercise Questions

6

If SinA = 1/2, cosB = , where π/2<A < π And 0 <B < π/2, find the following:

(i) tan(A +B)(ii) tan(A -B)