If α And β are two solutions of the equation Atanx + Bsecx = c, then find the values of sin(α + β).

Given equation Atanx + Bsecx = c


c – Atanx = Bsecx


Squaring onBoth sides,


(c – Atanx)2 = (Bsecx)2


c2 + A2tan2 x – 2actan x =B2sec2 x


c2 +A2 tan2 x – 2ac tan x = B2(1 + tan2 x)


(a2 –B2) tan2 x – 2ac tan x +(c2 –B2) = 0


There are two solutions tan α And tan β in this quadratic.



We know that




34