Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:

3x2 + 4y2 - 12x - 8y + 4 = 0

Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse 3x2 + 4y2 - 12x - 8y + 4 = 0.



3x2 + 4y2 - 12x - 8y + 4 = 0


3(x2 - 4x + 4) + 4(y2 - 2y + 1) - 12 = 0


3(x - 2)2 + 4(y - 1)2 = 12




Comparing with the standard form


Centre = (p,q) = (2,1)


Here a2>b2


eccentricity(e) =





Length of the major axis 2a = 2(2) = 4


Length of the minor axis 2b = = 2


Foci = (p±ae,q)


Foci =


Foci =


Foci = (3,1) and (1,1)


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