Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:

x2 + 4y2 - 2x = 0

Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse x2 + 4y2 - 2x = 0.



x2 + 4y2 - 2x = 0


(x2 - 2x + 1) + 4(y2) - 1 = 0


(x - 1)2 + 4(y - 0)2 = 1




Comparing with the standard form


Centre = (p,q) = (1,0)


Here a2>b2


eccentricity(e) =





Length of the major axis 2a = 2(1) = 2


Length of the minor axis 2b = = 1


Foci = (p±ae,q)


Foci =


Foci =


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