If S and S’ are two foci of the ellipse and B is an end of the minor axis such that Δ BSS’ is equilateral, then write the eccentricity of the ellipse.
Given that S and S’ are the foci of the ellipse .
It is told that ΔBSS’ is equilateral, where B is the end of the minor axis. We need to find the eccentricity of the ellipse.
Let us assume that B = (0,b)
We know that foci of the ellipse are (±ae,0).
We know that the distance between the foci is 2ae.
Let us find the distance SB
We know that the distance between the points (x1,y1) and (x2,y2) is .
⇒
⇒ .
We know that sides of an equilateral triangle are equal.
⇒ SB = 2ae
⇒ SB2 = 4a2e2
⇒ a2e2 + b2 = 4a2e2
We know that b2 = a2(1 - e2),
⇒ a2e2 + a2 - a2e2 = 4a2e2
⇒ a2 = 4a2e2
⇒
⇒
⇒ .