For the ellipse 12x2 + 4y2 + 24x – 16y + 25 = 0
Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse 12x2 + 4y2 + 24x - 16y + 25 = 0.
⇒ 12x2 + 4y2 + 24x - 16y + 25 = 0
⇒ 12(x2 + 2x + 1) + 4(y2 - 4y + 4) - 3 = 0
⇒ 12(x + 1)2 + 4(y - 2)2 = 3
⇒
⇒
Comparing with the standard form
⇒ Centre = (p,q) = (1, - 2)
Here b2>a2
⇒ eccentricity(e) =
⇒
⇒
⇒
Length of the major axis 2b =
Length of the minor axis 2a = = 1
∴ The correct option is D