Of all the closed cylindrical cans (right circular), which enclose a given volume of 100 cm3, which has the minimum surface area?

Let the radius and height of right circular cylinder be r and h respectively.


Given: Volume of Cylindrical can = 100 cm3


Volume of a cylinder = πr2h


πr2h = 100


… 1


Surface of a cylinder, S = 2πrh + 2πr2


From equation we get,




Condition for maxima and minima








So, for


>0


This is the condition for minima


From equation 1,



Hence, required dimensions of cylinders are radius = and height =


5