A straight line is drawn through a given point P (1, 4). Determine the least value of the sum of the intercepts on the coordinate axes.


Let us the slope of the line passing through the point P(1,4) be m.


We know that equation of a straight line passing through the point (x1,y1) and having slope m is given by:


y - y1 = m(x - x1)


The equation of the straight line is:


y - 4 = m(x - 1)


mx - y = m - 4




This resembles the standard form , where a is x - intercept and b is y - intercept.


Here x - intercept and b = 4 - m


According to the problem, we need sum of intercepts to be minimum,


Let us take the sum of intercepts to be S,


S = a + b




Let us assume S is the function of m,


We know that for maxima and minima,





4 - m2 = 0 ( m2>0)


m = ±2


Differentiating S again




At m = - 2




>0(Minima)


At m = + 2




<0(Maxima)


We have got minima for m = - 2


Using this value we find the sum of intercepts:




Smin = 3 + 6


Smin = 9


The least value of sum of intercepts is 9.


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