Let 
and 
Find each of the following :
i. 2A – 3B
ii. B – 4C
iii. 3A – C
iv. 3A – 2B + 3C
(i) 2A=
=
= 3B=
=
= 2A-3B=
-
=
= 
Hence, 2A-3B=
(ii) 4C=
=
B-4C=
-
=
=
Hence, B-4C=
(iii) 3A= 
= 3A-C=
-
= 
=
Hence, 3A-C=
(iv) 3A=
=
= 2A=
=
= 3C=
=
= 3A-2B+3C=
-
+
= 
=
Hence, 3A-2B+3C=
2