Since the form is indeterminant

Method 1: factorization

Since a³ + b³ = (a + b)(a² + b²-ab) & a²-b² = (a + b)(a-b)

= (-1)² + (1)² - (-1)

= 3

Method 2: By L hospital rule:

Differentiating numerator and denominator separately:

= 3(-1)²

= 3