How many four digit different numbers, greater than 5000 can be formed with the digits 1, 2, 5, 9, 0 when repetition of digits is not allowed?

In the question, we have to find the possible number of 4 digit numbers greater than 5000 formed by the numbers 0, 1, 2, 5, 9 when repetition of digits is not allowed.

We will use the concept of multiplication because there are four sub jobs dependent on each other because a number appearing on any one place will not appear in any other place.


For the first place from left we have two choices 5 and 9 because only then our number will be greater than 5000 , for the second place we have 4 choices because out of two one is assigned to the first position from left and total choice of numbers are 5 , so 5 - 1 = 4 , the number of choices will decrease by one as we keep on going right side.


The number of ways in which we can form six digit numbers with the help of given numbers is 2 × 4 × 3 × 2 = 2 × 4! = 2 × 24 = 48


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