Given: sum of first three terms is 24

To find: the first three terms of AP

Assume the first three terms are a - d, a, a + d where a is the first term and d is the common difference

So, sum of first three terms is a - d + a + a + d = 24

3a = 24

a = 8

given that the product of three terms is 440

so a³ - ad² = 440

substituting a = 8

8³ - 8d² = 440

512 - 8d² = 440

72 = 8d²

d = 3 or d = - 3

hence the given terms are a - d, a, a + d which is 5, 8, 11 or 11, 8, 5