assume the angles are a - 2d, a - d, a + d, a + 2d

We know that the sum of all angles in a quadrilateral is 360

Given: d = 10

To find: angles of the quadrilateral

So, a - 2d + a - d + a + d + a + 2d = 360

4a = 360

a = 90

hence the angles are a - 2d, a - d, a + d, a + 2d which is 70, 80, 100, 110