How many terms are there in the A.P. whose first and fifth terms are - 14 and 2 respectively and the sum of the terms is 40?
given the first term is - 14, from which we can say that a = - 14
To find: the number of terms in an AP whose first and fifth terms is - 14 and 2 respectively, and the sum of the terms is 40
Given fifth term is 2, so a + 4d = 2
- 14 + 4d = 2
d = 4
we know that the sum of AP is given by the formula:
now substituting the values in the above equation
4n2 - 32n - 80 = 0
n2 - 8n - 20 = 0
solving we get n as 10 or - 2
Since the number of terms cannot be negative hence n is 10