If the 12th term of an A.P. is - 13 and the sum of the first 4 terms is 24, what is the sum of the first 10 terms?

assuming an AP whose first term is a and the common difference is d

To find: the sum of first 10 terms


Given 12th term is - 13


So, a + 11d = - 13...(i)


Given the sum of first four terms is 24


So 4a + 6d = 24…(ii)


Solving (i) and (ii) we get


a = 9 and d = - 2


we know that the sum of AP is given by the formula:



substituting the values in the above equation



s = 0


22