If the sum of a certain number of terms of the A.P. 25, 22, 19, …. is 116. Find the last term
given an AP whose first term is 25 and the common difference is - 3
To find: the last term of a given AP
we know that the sum of AP is given by the formula
Solving we get
3n2 - 53n + 232 = 0
n = 8 or
n cannot be a fraction hence we choose n as 8
Now for the finding number of terms, the formula is
solving we get the last term as 4