If the sum of a certain number of terms of the A.P. 25, 22, 19, …. is 116. Find the last term

given an AP whose first term is 25 and the common difference is - 3

To find: the last term of a given AP


we know that the sum of AP is given by the formula




Solving we get


3n2 - 53n + 232 = 0


n = 8 or


n cannot be a fraction hence we choose n as 8


Now for the finding number of terms, the formula is




solving we get the last term as 4


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