Let A₁, A₂, A₃, A₄, A₅, A₆ be the 7 AM Between 15 And - 13

Then, 15, A₁, A₂, A₃, A₄, A₅, A₆, - 13 are in AP

We know,

A_n = a + (n - 1)d

A_{8 =} - 13 = 15 + (8 - 1)d

d = -4

Hence,

A₁ = a + d = 15 - 4 = 11

A₂ = A1 + d = 11 - 4 = 7

A₃ = A2 + d = 7 - 4 = 3

A₄ = A3 + d = 3 - 4 = -1

A₅ = A4 + d = -1 - 4 = -5

A₆ = A5 + d = -5 - 4 = -9