Evaluate the following limits:
As we need to find
We can directly find the limiting value of a function by putting the value of the variable at which the limiting value is asked if it does not take any indeterminate form (0/0 or ∞/∞ or ∞-∞,1∞ .. etc.)
Let Z =
As it is taking indeterminate form-
∴ we need to take steps to remove this form so that we can get a finite value.
Z =
Take the log to bring the power term in the product so that we can solve it more easily.
Taking log both sides-
log Z =
⇒ log Z =
{∵ log am = m log a}
using algebra of limits-
⇒ log Z =
⇒ log Z =
⇒ log Z =
As, 1-cos x = 2sin2(x/2)
∴ log Z =
Let (x-1)/2 = y
As x→1 ⇒ y→0
∴ Z can be rewritten as
Log Z =
⇒ log Z =
Use the formula -
∴ log Z =
⇒ log Z =
∴ Z =
Hence,