In a GP the 3rd term is 24, and the 6th term is 192. Find the 10th term.
Tn = arn-1
a = a, r =?, Tn = 24 n = 3
a = a, r =?, Tn = 192 n = 6
∴ 24 = a.r3-1
⇒ 24 = a.r2…(1)
∴ 192 = a.r6-1
⇒ 192 = a.r5…(2)
Divide (2) by (1) we get
⇒
⇒ r3 = 8
⇒ r = 2
Substituting r in 2 we get
a = 6
T10 = 6.210-1
= 6.29
= 3072.