If the A.M. of two positive numbers a and b (a > b) is twice their geometric mean. Prove that : a : b = (2 + ) : (2 –
).
Let the two numbers be a and b.
GM = √ab
According to the given condition,
⇒
a + b = 4√ab …(1)
(a + b)2 = 16ab
Also,
(a – b)2 = (a + b)2 – 4ab
= 16ab – 4ab
= 12ab
⇒ a – b = 2√3ab…(2)
Adding (1) and (2), we obtain
2a = (4 + 2√3 )√ab
a = (2 + √3)√ab
substituting the value of a in (1), we obtain,
b =(2 – √3)√ab
∴
Thus, the required ratio is (2+√3) : (2–√3).