The sum of 10 terms of the series is
Let S = √2 + √6 + √18 + ……….
It can also be written as,
S = √2(1 + √3 + 3 + 3√3 + …….)
Now,
1 + √3 + 3 + 3√3 + …… is a G.P with common ratio √3
Sum of the 10 terms will be given by,
S10 = 121(√6 + √2)