A(1,-2) and B(2,5) are two points. The lines OA, OB are produced to C and D respectively such that OC = 2OA and OD = 2OB. Find CD.
Given:
A(1, -2) and B(2, 5) are two points.
OC = 2OA …(i)
and OD = 2OB …(ii)
Adding (i) and (ii), we get
OC + OD = 2OA + 2OB
⇒ CD = 2[OA + OB]
⇒ CD = 2[AB] …(iii)
Now, we find the distance between A and B
d(A,B) = √(x2 – x1)2 + (y2 – y1)2
= √(2 – 1)2 + {5 – (-2)}2
= √(1)2 + (5 + 2)2
= √1 + 49
= √50
= 5√2
Putting the value in eq. (iii), we get
CD = 2 × 5√2
= 10√2