A(1,-2) and B(2,5) are two points. The lines OA, OB are produced to C and D respectively such that OC = 2OA and OD = 2OB. Find CD.


Given:


A(1, -2) and B(2, 5) are two points.


OC = 2OA …(i)


and OD = 2OB …(ii)


Adding (i) and (ii), we get


OC + OD = 2OA + 2OB


CD = 2[OA + OB]


CD = 2[AB] …(iii)


Now, we find the distance between A and B


d(A,B) = √(x2 – x1)2 + (y2 – y1)2


= √(2 – 1)2 + {5 – (-2)}2


= √(1)2 + (5 + 2)2


= √1 + 49


= √50


= 5√2


Putting the value in eq. (iii), we get


CD = 2 × 5√2


= 10√2


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