Without using the distance formula, show that points (– 2, – 1), (4, 0), (3, 3) and (– 3, 2) are the vertices of a parallelogram.

To Prove: Given points are of Parallelogram.
Explanation: Let us Assume that we have points, A (– 2, – 1), B(4, 0), C(3, 3) and D(– 3, 2), are joining the sides as AB, BC, CD, and AD.
The formula used: The slope of the line, m = ![]()
Now, The slope of Line AB, mAB = ![]()
mAB = ![]()
The slope of BC, mBC = ![]()
mBC = ![]()
Now, The slope of Line CD, mCD = ![]()
mCD = ![]()
The slope of AD, mAD = ![]()
mAD = ![]()
Here, We can see that, mAB = mCDand mBC = mAD
i.e, AB
CD and BC
AD
We know, If opposite side of a quadrilateral are parallel that it is parallelogram.
Hence, ABCD is a Parallelogram.