Show that the following statement is true by the method of the contrapositive

p : “If x is an integer and x2 is odd, then x is also odd.”

Let us Assume that q and r be the statements given

q: x is an integer and x2 is odd.


r: x is an odd integer.


since the given statement can be written as :


p: if q, then r.


Let r be false . then,


x is not an odd integer, then


x is an even integer


x = (2n) for some integer n


x2 = 4n2


x2 is an even integer


Thus, q is False


Therefore, r is false q is false


Hence, p: “ if q, then r” is a true statement.


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