When a boat is partially immersed in water, it displaces 600 kg of water. How much is the buoyant force acting on the boat in Newton? (g = 10 m s -2 )

Question

Philoid · Accepted Answer

Mass of water displaced = 600kg

Weight of water displaced, W =m x g

=600 x 10

=6000N

Since, the weight of water displaced by the boat is 6000N.

Therefore the buoyant force acting on the boat will also be 6000N.

When a boat is partially immersed in water, it displaces 600 kg of water. How much is the buoyant force acting on the boat in Newton? (g = 10 m s-2)

When a boat is partially immersed in water, it displaces 600 kg of water. How much is the buoyant force acting on the boat in Newton? (g = 10 m s^-2)