If a, b, c are in G.P., prove that are in A.P.
Given:
a, b and c are in GP
∴ b2 = ac {property of geometric mean}
Taking log on both sides with base m –
logm b2 = logm ac
⇒ logm b2 = logm a + logm c {using property of log}
⇒ 2logm b = logm a + logm c …equation 1
Note: If three numbers a,b and c are in AP,we can say that –
2b = a + c
As equation 1 matches the form above, So
⇒ logm a, logm b and logm c are in AP. …(1)
Now, applying base changing formula we get
⇒ logab =
∴ Applying base change on 1, we get
⇒ are in A.P
Hence, proved