If xa = xb/2zb/2 = zc, then prove that
are in A.P.
Take logs of each expression, using ln(xa) = a ln(x) etc
ln (p*q) = ln(p) + ln(q):
Given,
xa = xb/2zb/2 = zc
Taking log on each term –
⇒
…(1)
The equality of the first and third expressions tells us that
⇒
…(2)
The second expression is equal to
⇒ ![]()
⇒
{using equation 1}
∴ ![]()
Divide through out by ln x
∴ a = b/2 + ab/2c
⇒ 2ac = bc + ab
Dividing the equation by abc –
⇒ ![]()
From this
are in GP.