Given,

f(x) =

⇒ f(x) =

⇒ f(x) = 2x + 3 + 4x ^{– 1}

we need to find f’(x), so differentiating both sides with respect to x –

∴ 2x + 3 + 4x ^{– 1}

Using algebra of derivatives –

⇒ f’(x) =

Use the formula:

∴ f’(x) = 2 + 0 + 4( – 1)x ^{– 1 – 1}

⇒ f’(x) = 2 – 4x ^{– 2}

∴ f’(x) = 2 – 4x ^{– 2}