If x < 2, then write the value of 
Let 
Now,
From above,
x2 – 4x + 4 > 0
(x – 2)2 > 0
x > 2
But x < 2. Therefore, 
does not exist for the given function.
3
If x < 2, then write the value of
Let
Now,
From above,
x2 – 4x + 4 > 0
(x – 2)2 > 0
x > 2
But x < 2. Therefore, does not exist for the given function.