If f(x) = 1 – x + x2 – x3 + ….. – x99 + x100, then f’(1) equals

As, f(x) = 1 – x + x2 – x3 + ….. – x99 + x100


We know that,






f’(1) = –1+2–3+…–99+100


f’(1) = (2+4+6+8+….+98+100) – (1+3+5+…+97+99)


Both terms have 50 terms


We know that sum of n terms of an A.P =


f’(1) =


Clearly above solution suggests that only 1 result is possible which is 50.


Hence,


Only option (d) is the correct answer.

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