If f(x) = x100 + x99 + …..+ x + 1, then f’(1) is equal to

As, f(x) = 1 + x + x2 + x3 + ….. + x99 + x100


We know that,






f’(1) = 1 + 2 + 3 + … + 99 + 100 (total 100 terms)


We know that sum of n terms of an A.P =


f’(1) =


Clearly, the above solution suggests that only 1 result is possible which is 5050.


Hence,


The only option (a) is the correct answer.

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