Given: Two dice are thrown.

To Find: Describe the given events.

Explanation: when two dice are thrown then the no. of possible outcomes are 6² = 36

Now, According to the question,

A = Getting an even number of the first die.

A = {(2, 1)(2, 2)(2, 3)(2, 4)(2, 5)(2, 6)(4, 1)(4, 2)(4, 3)(4, 4)(6, 1)(6, 2)(6, 3)(6, 4)(6, 5)(6, 6)}

B = Getting an odd number on the first dice

B = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5)(5, 6)}

C = Getting at most 5 as the sum of numbers on the two dices.

C = {(1, 1)(1, 2)(1, 3)(1, 4)(2, 1)(2, 2)(2, 3)(3, 1)(3, 2)(4, 1)}

D = Getting a sum greater than 5 but less than 10

D = {(1, 5)(1, 6) (2, 4)(2, 5) (2, 6)(3, 3)(3, 4)(3, 5)(3, 6)(4, 2)(4, 3)(4, 4)(4, 5)(5, 1) (5, 2)(5, 3) (5, 4)(6, 1) (6, 2)(6, 3)}

E = Getting at least 10 as the sum of numbers on the dices

{(4, 6)(5, 5)(5, 6)(6, 4)(6, 5)(6, 6)}

F = Getting an odd number on one of the dices

{(1, 2)(1, 4)(1, 6)(2, 1)(2, 3)(2, 5)(3, 2)(3, 4)(3, 6)(4, 1)(4, 3)(4, 5)(5, 2)(5, 4)(5, 6)(6, 1)(6, 3)(6, 5)

Now,

(i) A and B = AՌB = Փ

Since, There is no common events in Both A and B so the intersection is Null (Փ).

B or C = BUC

BUC = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5)(5, 6)(2, 1)(2, 2)(2, 3)(4, 1)}

B and C = BՌC

BՌC = {(1, 1), (1, 2)(1, 3)(1, 4)(3, 1)(3, 2)}

A and E = AՌE

AՌE = {(4, 6)(6, 4)(6, 5)(5, 6)(6, 6)}

A or F = AUF

AUF = {(2, 1)(2, 2)(2, 3)(2, 4)(2, 5)(2, 6)(4, 1)(4, 2)(4, 3)(4, 4)(6, 1)(6, 2)(6, 3)(6, 4)(6, 5)(6, 6)(1, 2)(1, 4)(1, 6)(3, 2)(3, 4)(3, 6)(4, 5)(5, 2)(5, 4)(5, 6)}

(ii)

(a) True, because AՌB = Փ

(b) True, because AՌB = Փ and AUB = S

(c) False, because AՌC = Փ

(d) False, because CՌD = Փ but CUD≠S

(e) True, because CՌDՌE = Փ and CUDUE = S

(f) True, because A’ՌB’ = Փ

(g) False, because AՌBՌF = Փ and AUBUF = S