A die is thrown. Find the probability of getting:
(i) a prime number
(ii) 2 or 4
(iii) a multiple of 2 or 3
given: die is thrown
Therefore, the total number of outcomes is six
n(S)=6
formula:
(i) let E be the event of getting a prime number
E= {2,3,5}
n(E)=3
(ii) let E be the event of getting 2 or 4
E= {2,4}
n(E)=2
(iii) let E be the event of getting a multiple of 2 or 3
E= {2,3,4,6}
n(E)=4