Three coins are tossed together. Find the probability of getting:

(i) exactly two heads


(ii) at least two heads


(iii) at least one head and one tail

given: three coins are tossed together

formula:


Total number of possible outcomes are 23=8


(i) let E be the event of getting exactly two heads


E= {(H, H, T) (H, T, H) (T, H, H)}


n(E)=3




(ii) let E be the event of getting at least two heads


E= {(H, H, T) (H, T, H) (T, H, H) (H, H, H)}


n(E)=4




(iii) let E be the event of getting at least one head and one tail


E= {(H, T, T) (T, H, T) (T, T, H) (H, H, T) (H, T, H) (T, H, H)}


n(E)=6




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