Three coins are tossed together. Find the probability of getting:
(i) exactly two heads
(ii) at least two heads
(iii) at least one head and one tail
given: three coins are tossed together
formula:
Total number of possible outcomes are 23=8
(i) let E be the event of getting exactly two heads
E= {(H, H, T) (H, T, H) (T, H, H)}
n(E)=3
(ii) let E be the event of getting at least two heads
E= {(H, H, T) (H, T, H) (T, H, H) (H, H, H)}
n(E)=4
(iii) let E be the event of getting at least one head and one tail
E= {(H, T, T) (T, H, T) (T, T, H) (H, H, T) (H, T, H) (T, H, H)}
n(E)=6