Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10
given: three dice are rolled
formula:
so, we have to determine the probability of getting the sum of digits on dice greater than 10
total number of possible outcomes are 62=36
therefore n(S)=36
let E be the event of getting same number on all the three dice
E= {(5,6) (6,5) (6,6)}
n(E)=3