Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10

given: three dice are rolled

formula:


so, we have to determine the probability of getting the sum of digits on dice greater than 10


total number of possible outcomes are 62=36


therefore n(S)=36


let E be the event of getting same number on all the three dice


E= {(5,6) (6,5) (6,6)}


n(E)=3




10