Tickets numbered from 1 to 20 are mixed up together and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 7?
given: numbered tickets from 1 to 20
formula:
to find the probability of the ticket drawn having a number which is a multiple of 3 or 7
Since one ticket is drawn from a lot of mixed number, total possible outcomes are
n(S)=20C1=20
let E be the event of getting ticket which has number that is multiple of 3 or 7
E= {3,6,9,12,15,18,7,14}
n(E)=8