given: word “CLIFTON”

formula:

In the random arrangement of the alphabets of word “CLIFTON” we have to find the probability that vowels come together

total possible outcomes of arranging the alphabets are 7!

therefore n(S)=7!

let E be the event that vowels come together

number of vowels in SOCIAL is I, O

therefore, number of ways to arrange them so (I, O) come together

n(E)= 6! × 2!