A box contains 10 red marbles, 20 blue marbles and 30 green marbles. 5 marbles are drawn at random. From the box, what is the probability that:

(i) al are blue?


(ii) at least one is green?

given: box containing 10 red, 20 blue and 30 green marbles

formula:


five marbles are drawn from the given box, total possible outcomes are 60C5


therefore n(S)=60C5


(i) let E be the event of getting all blue balls


n(E)= 20C5




(ii) let E be the event of getting at least one green


let E’ be the event of getting no green


E’= {(5B) (1R 4B) (2R 3B) (3R 2B) (4R 1B) (5R)}


5B=20C5


1R 4B=10C120C4


2R 3B=10C220C3


3R 2B=10C320C2


4R 1B=10C420C1


5R= 10C5


P(E) =1-P(E’)





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