A box contains 10 red marbles, 20 blue marbles and 30 green marbles. 5 marbles are drawn at random. From the box, what is the probability that:
(i) al are blue?
(ii) at least one is green?
given: box containing 10 red, 20 blue and 30 green marbles
formula:
five marbles are drawn from the given box, total possible outcomes are 60C5
therefore n(S)=60C5
(i) let E be the event of getting all blue balls
n(E)= 20C5
(ii) let E be the event of getting at least one green
let E’ be the event of getting no green
E’= {(5B) (1R 4B) (2R 3B) (3R 2B) (4R 1B) (5R)}
5B=20C5
1R 4B=10C120C4
2R 3B=10C220C3
3R 2B=10C320C2
4R 1B=10C420C1
5R= 10C5
P(E) =1-P(E’)