Find the equation of a straight line:

(i) with slope 2 and y – intercept 3;


(ii) with slope – 1/ 3 and y – intercept – 4.


(iii) with slope – 2 and intersecting the x–axis at a distance of 3 units to the left of origin.

(i) Here, The slope is 2 and the coordinates are (0, 3)

Now, The required equation of line is


y = mx + c


y = 2x + 3


(ii) Here, The slope is – 1/3 and the coordinates are (0, – 4)


Now, The required equation of line is


y = mx + c


y = x – 4


3y + x = – 12


(iii) Here, The slope is – 2 and the coordinates are (– 3, 0)


Now, The required equation of line is y – y1 = m (x – x1)


y – 0 = – 2(x + 3)


y = – 2x – 6


2x + y + 6 = 0


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